iz^2-(2+i)z+1=0

Solution for iz^2-(2+i)z+1=0 equation:

Simplifying
iz2 + -1(2 + i) * z + 1 = 0

Reorder the terms for easier multiplication:
iz2 + -1z(2 + i) + 1 = 0
iz2 + (2 * -1z + i * -1z) + 1 = 0

Reorder the terms:
iz2 + (-1iz + -2z) + 1 = 0
iz2 + (-1iz + -2z) + 1 = 0

Reorder the terms:
1 + -1iz + iz2 + -2z = 0

Solving
1 + -1iz + iz2 + -2z = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1iz + iz2 + -1 + -2z = 0 + -1

Reorder the terms:
1 + -1 + -1iz + iz2 + -2z = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1iz + iz2 + -2z = 0 + -1
-1iz + iz2 + -2z = 0 + -1

Combine like terms: 0 + -1 = -1
-1iz + iz2 + -2z = -1

Add '2z' to each side of the equation.
-1iz + iz2 + -2z + 2z = -1 + 2z

Combine like terms: -2z + 2z = 0
-1iz + iz2 + 0 = -1 + 2z
-1iz + iz2 = -1 + 2z

Reorder the terms:
1 + -1iz + iz2 + -2z = -1 + 2z + 1 + -2z

Reorder the terms:
1 + -1iz + iz2 + -2z = -1 + 1 + 2z + -2z

Combine like terms: -1 + 1 = 0
1 + -1iz + iz2 + -2z = 0 + 2z + -2z
1 + -1iz + iz2 + -2z = 2z + -2z

Combine like terms: 2z + -2z = 0
1 + -1iz + iz2 + -2z = 0

The solution to this equation could not be determined.